1: \(\dfrac{x}{4}=2-\dfrac{x}{3}\)
=>\(\dfrac{x}{4}+\dfrac{x}{3}=2\)
=>\(x\cdot\dfrac{7}{12}=2\)
=>\(x=2:\dfrac{7}{12}=2\cdot\dfrac{12}{7}=\dfrac{24}{7}\)
2: \(\dfrac{2x-1}{5}-\dfrac{x+1}{2}=0\)
=>\(\dfrac{2\left(2x-1\right)-5\left(x+1\right)}{10}=0\)
=>2(2x-1)-5(x+1)=0
=>4x-2-5x-5=0
=>-x-7=0
=>x+7=0
=>x=-7
3: \(\dfrac{2x}{3}-\dfrac{2x+5}{6}=\dfrac{1}{2}\)
=>\(\dfrac{4x}{6}-\dfrac{2x+5}{6}=\dfrac{3}{6}\)
=>4x-2x-5=3
=>2x=8
=>x=4
4: \(3=x-2\)
=>x-2=3
=>x=3+2=5
5: \(7=x+4\)
=>x+4=7
=>x=7-4=3
6: 2x-(3-5x)=4(x+3)
=>\(2x-3+5x=4x+12\)
=>7x-3=4x+12
=>3x=15
=>x=5
7: \(5-\left(6-x\right)=4\left(3-2x\right)\)
=>\(12-8x=5-6+x=-1+x\)
=>-8x-x=-1-12
=>-9x=-13
=>\(x=\dfrac{13}{9}\)
8: \(5\left(x-3\right)-4=2\left(x-1\right)+7\)
=>\(5x-15-4=2x-2+7\)
=>5x-19=2x+5
=>3x=24
=>x=8
9: \(5\left(x-3\right)-4=2\left(x-1\right)+7\)
=>\(5x-15-4=2x-2+7\)
=>5x-19=2x+5
=>3x=24
=>x=8
10: 4(3x-2)-3(x-4)=7x+20
=>\(12x-8-3x+12=7x+20\)
=>9x+4=7x+20
=>2x=16
=>x=8
11: \(\dfrac{8x-3}{4}-\dfrac{3x-2}{2}=\dfrac{2x-1}{2}+\dfrac{x+3}{4}\)
=>\(\dfrac{8x-3-2\left(3x-2\right)}{4}=\dfrac{2\left(2x-1\right)+x+3}{4}\)
=>8x-3-6x+4=4x-2+x+3
=>2x+1=5x+1
=>-3x=0
=>x=0
