Câu hỏi của phudepzai

a: f(2)=0=>\(\left(6-3m\right)\cdot2+m-6=0\)=>\(12-6m+m-6=0\)=>6-5m=0=>5m=6=>\(m=\dfrac{6}{5}\)b: f(-1)=8=>\(\left(6-3m\right)\cdot\left(-1\right)+m-6=8\)=>-6+3m+m-6=8=>4m-12=8=>4m=20=>m=5Khi m=5 thì \(a=6-3m=6-3\cdot5=-9;b=m-6=5-6=-1\)Câu trả lời: a: f(2)=0=>\(\left(6-3m\right)\cdot2+m-6=0\)=>\(12-6m+m-6=0\)=>6-5m=0=>5m=6=>\(m=\dfrac{6}{5}\)b: f(-1)=8=>\(\left(6-3m\right)\cdot\left(-1\right)+m-6=8\)=>-6+3m+m-6=8=>4m-12=8=>4m=20=>m=5Khi m=5 thì \(a=6-3m=6-3\cdot5=-9;b=m-6=5-6=-1\)