Question

Answer 1

25: \(\dfrac{3x+2}{2}+\dfrac{5-2x}{3}=\dfrac{11}{6}\)

=>\(\dfrac{3\left(3x+2\right)+2\left(5-2x\right)}{6}=\dfrac{11}{6}\)

=>\(3\left(3x+2\right)+2\left(5-2x\right)=11\)

=>\(9x+6+10-4x=11\)
=>5x=11-16=-5

=>\(x=-\dfrac{5}{5}=-1\)

26: \(\dfrac{x+2}{4}+\dfrac{2x-3}{3}=\dfrac{x-12}{6}\)

=>\(\dfrac{3\left(x+2\right)+4\left(2x-3\right)}{12}=\dfrac{2x-24}{12}\)

=>\(3\left(x+2\right)+4\left(2x-3\right)=2x-24\)

=>\(3x+6+8x-12=2x-24\)

=>\(11x-6=2x-24\)

=>9x=-18

=>\(x=-\dfrac{18}{9}=-2\)

27: \(\dfrac{2x-1}{3}-\dfrac{x-1}{2}+\dfrac{x+1}{6}=1\)

=>\(\dfrac{2\left(2x-1\right)-3\left(x-1\right)+x+1}{6}=1\)

=>\(\dfrac{4x-2-3x+3+x+1}{6}=1\)

=>\(2x+2=6\)

=>2x=4

=>x=2