H24
NT

a: \(\dfrac{1}{2}x\left(4x^3-\dfrac{4}{3}x\right)\)

\(=\dfrac{1}{2}x\cdot4x^3-\dfrac{1}{2}x\cdot\dfrac{4}{3}x\)

\(=2x^4-\dfrac{2}{3}x^2\)

b: \(\dfrac{4}{3}y\left(-3y^3+\dfrac{9}{12}y^2\right)\)

\(=\dfrac{4}{3}y\cdot\left(-3\right)y^3+\dfrac{4}{3}\cdot\dfrac{9}{12}\cdot y\cdot y^2\)

\(=-4y^4+y^3\)

c: \(0,25x^3\left(24x^3-\dfrac{4}{5}x^2+1,6\right)\)

\(=0,25\cdot x^3\cdot24x^3-0,25x^3\cdot\dfrac{4}{5}x^2+0,25\cdot x^3\cdot1,6\)

\(=6x^6-\dfrac{1}{5}\cdot x^5+0,4x^3\)

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