Do \(-1\le x;y;z\le1\)
\(\Rightarrow\left(1-x\right)\left(1-y\right)\left(1-z\right)+\left(x+1\right)\left(y+1\right)\left(z+1\right)\ge0\)
\(\Leftrightarrow2xy+2yz+2zx+2\ge0\)
\(\Leftrightarrow\left(x+y+z\right)^2-\left(x^2+y^2+z^2\right)+2\ge0\)
\(\Leftrightarrow x^2+y^2+z^2\le2\)
Dấu "=" xảy ra khi \(\left(x;y;z\right)=\left(-1;0;1\right)\) và các hoán vị