\(\left(\dfrac{2x}{3}-3\right):\left(-10\right)=\dfrac{2}{5}\)
\(\dfrac{2x}{3}-3=\dfrac{2}{5}\cdot10=4\)
\(\dfrac{2x}{3}=4+3=7\)
\(2x=7\cdot3=21\)
\(x=21:2=10,5\)
Vậy \(x=10,5\)
\(\dfrac{8}{7}-\dfrac{1}{7}:\left(\dfrac{y}{3}-2\right)=-1\)
\(1:\left(\dfrac{y}{3}-2\right)=-1\)
\(\dfrac{y}{3}-2=1:\left(-1\right)=-1\)
\(\dfrac{y}{3}=\left(-1\right)+2=1\)
\(y=1\cdot3=3\)
Vậy \(y=3\)
\(2\dfrac{3}{5}-\dfrac{9}{5}\cdot\sqrt{\dfrac{1}{9}}+\left(-1\right)^{2020}+\left|2021\right|\)
\(\dfrac{4}{5}\cdot\dfrac{1}{\sqrt{9}}+1+2021\)
\(\dfrac{4}{5}\cdot\dfrac{1}{3}+2022\)
\(\dfrac{4}{15}+2022\)
\(2022\dfrac{4}{15}\)
\(\left|\dfrac{-5}{3}\right|+\left(\dfrac{-11}{4}\right):\sqrt{\dfrac{1}{16}}-\left(\dfrac{20}{21}\right)^0\)
\(\dfrac{5}{3}+\left(\dfrac{-11}{4}\right):\dfrac{1}{\sqrt{16}}-1\)
\(\dfrac{-13}{12}:\dfrac{1}{4}-1\)
\(-\dfrac{13}{3}-1\)
\(-\dfrac{16}{3}\)