a) 2(x - 7) + 25 = 15
2(x - 7) = 15 - 25
2(x - 7) = -10
x - 7 = -10 : 2
x - 7 = -5
x = -5 + 7
x = 2
b) x ∈ Ư(50) = {-50; -25; -10; -5; -2; -1; 1; 2; 5; 10; 25; 50}
Mà -5 < x < 5
⇒ x ∈ {-2; -1; 1; 2}
a) \(2\left(x-7\right)+25=15\)
\(\Rightarrow2\left(x-7\right)=15-25\)
\(\Rightarrow2\left(x-7\right)=-10\)
\(\Rightarrow x-7=-10:2\)
\(\Rightarrow x-7=-5\)
\(\Rightarrow x=-5+7\)
\(\Rightarrow x=2\left(tm\right)\)
b) Ta có: \(x\inƯ\left(50\right)\)
\(\Rightarrow x\in\left\{1;2;5;10;25;50;-1;-2;-5;-10;-25;-50\right\}\)
Mà: \(-5< x< 5\) nên \(x\in\left\{-2;-1;1;2\right\}\)
a) 2(x - 7) + 25 = 15
2(x - 7) = 15 - 25
2(x - 7) = -10
x - 7 = -10 : 2
x - 7 = -5
x = -5 + 7
x = 2
b) x ∈ Ư(50) = {-50; -25; -10; -5; -2; -1; 1; 2; 5; 10; 25; 50}
Mà -5 < x < 5
⇒ x ∈ {-2; -1; 1; 2}