Câu hỏi của Mon an

\(x^2-6y^2-xy-2x+6y\)\(=x^2-3xy+2xy-6y^2-2\left(x-3y\right)\)\(=\left(x-3y\right)\left(x+2y\right)-2\left(x-3y\right)\)\(=\left(x-3y\right)\left(x+2y-2\right)\)Câu trả lời: \(x^2-6y^2-xy-2x+6y\)\(=x^2-3xy+2xy-6y^2-2\left(x-3y\right)\)\(=\left(x-3y\right)\left(x+2y\right)-2\left(x-3y\right)\)\(=\left(x-3y\right)\left(x+2y-2\right)\)