Question

  

Answer 1

a:

ĐKXĐ: \(x\notin\left\{0\right\}\)

 \(\dfrac{5xy}{10x}=\dfrac{5xy:5x}{10x:5x}=\dfrac{y}{2}\)

b:

ĐKXĐ: \(x\notin\left\{1;-1\right\}\)

 \(\dfrac{2x+2}{x^2-1}=\dfrac{2\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}=\dfrac{2}{x-1}\)

c: 

ĐKXĐ: x<>-3

\(\dfrac{x+3}{6x+18}=\dfrac{x+3}{6\left(x+3\right)}=\dfrac{1}{6}\)

Answer 2

\(\dfrac{5xy}{10x}=\dfrac{5xy:5x}{10x:5x}=\dfrac{y}{2}\\ \dfrac{2x+2}{x^2-1}=\dfrac{2\left(x+1\right)}{\left(x-1\right)\left(x+1\right)}=\dfrac{2}{x-1}\\ \dfrac{x+3}{6x+18}=\dfrac{x+3}{6\left(x+3\right)}=\dfrac{1}{6}\)