Câu hỏi của Bi Bi

Question

Toru · Accepted Answer

$(-6x^2y^2+6x^3y^2)-(6x^3y^2+3x^4y^2)\=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2\=-6x^2y^2-3x^4y^2$Câu trả lời: $(-6x^2y^2+6x^3y^2)-(6x^3y^2+3x^4y^2)\=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2\=-6x^2y^2-3x^4y^2$

Hobiee · Answer

$\left(-6x^2y^2+6x^3y^2\right)-\left(6x^3y^2+3x^4y^2\right)\
=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2\
=\left(-6x^3y^2+6x^3y^2\right)-6x^2y^2-3x^4y^2\
=-6x^2y^2-3x^4y^2$Câu trả lời: $\left(-6x^2y^2+6x^3y^2\right)-\left(6x^3y^2+3x^4y^2\right)\
=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2\
=\left(-6x^3y^2+6x^3y^2\right)-6x^2y^2-3x^4y^2\
=-6x^2y^2-3x^4y^2$

HT.Phong (9A5) · Answer

$\left(-6x^2y^2+6x^3y^2\right)-\left(6x^3y^2+3x^4y^2\right)$$=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2$$=-6x^2y^2+\left(6x^3y^2-6x^3y^2\right)-3x^4y^2$$=-6x^2y^2-3x^4y^2$Câu trả lời: $\left(-6x^2y^2+6x^3y^2\right)-\left(6x^3y^2+3x^4y^2\right)$$=-6x^2y^2+6x^3y^2-6x^3y^2-3x^4y^2$$=-6x^2y^2+\left(6x^3y^2-6x^3y^2\right)-3x^4y^2$$=-6x^2y^2-3x^4y^2$

Câu hỏi

Khoá học trên OLM (olm.vn)