\(\left\{{}\begin{matrix}\dfrac{1}{2}y=x+2\\2x-3y=-8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x-\dfrac{1}{2}y=-2\\2x-3y=-8\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}2x-y=-4\\2x-3y=-8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2y=4\\2x-y=-4\end{matrix}\right.\\ \Leftrightarrow\left\{{}\begin{matrix}y=\dfrac{4}{2}=2\\x=\dfrac{-4+2}{2}=-1\end{matrix}\right.\\ Vây:\left(x;y\right)=\left(-1;2\right)\)
x+2=1/2y và 2x-3y=-8
=>2x+4=y và 2x-3y=-8
=>2x-y=-4 và 2x-3y=-8
=>2y=4 và 2x-y=-4
=>y=2 và 2x=-4+y=-4+2=-2
=>x=-1 và y=2
\(\left\{{}\begin{matrix}\dfrac{1}{2}y=x+2\\2x-3y=-8\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-y=-4\\2x-3y=-8\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}2y=4\\2x-y=-4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}y=2\\x=\dfrac{-4+y}{2}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=-1\\y=2\end{matrix}\right.\)
