\(C=\dfrac{\left(2^3\cdot3^2\right)^3\cdot\left(3^3\cdot2\right)^2}{\left(2^2\cdot3^3\right)^4}=\dfrac{2^9\cdot3^6\cdot3^6\cdot2^2}{2^8\cdot3^{12}}=\dfrac{2^{11}}{2^8}=2^3=8\)
\(D=\dfrac{3^{29}\left(11-3\right)}{2^2\cdot3^{28}}=\dfrac{8}{4}\cdot3=2\cdot3=6\)
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