Câu hỏi của Anngoc Anna

x1^2+x2^2=(x1+x2)^2-2x1x2=(-m)^2-2=m^2-2x1^3+x2^3=(x1+x2)^3-3x1x2(x1+x2)=(-m)^3-3*1*(-m)=-m^3+3m|x1-x2|=căn (x1-x2)^2\(=\sqrt{\left(x_1+x_2\right)^2-4x_1x_2}=\sqrt{\left(-m\right)^2-4}=\sqrt{m^2-4}\)Câu trả lời: x1^2+x2^2=(x1+x2)^2-2x1x2=(-m)^2-2=m^2-2x1^3+x2^3=(x1+x2)^3-3x1x2(x1+x2)=(-m)^3-3*1*(-m)=-m^3+3m|x1-x2|=căn (x1-x2)^2\(=\sqrt{\left(x_1+x_2\right)^2-4x_1x_2}=\sqrt{\left(-m\right)^2-4}=\sqrt{m^2-4}\)