Câu hỏi của Quyết Nguyễn

b: \(=\dfrac{2^4}{2^3}\cdot\dfrac{5^2}{5^3}\cdot\dfrac{11^2}{11}\cdot\dfrac{7}{7^2}=\dfrac{2}{5}\cdot\dfrac{11}{7}=\dfrac{22}{35}\)b: \(=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=\dfrac{3^3\cdot13}{-13}=-27\)b: \(=\dfrac{2^6\cdot3^6+3^6+3^6\cdot2^3}{73}\)=3^6(2^6+2^3+1)/73=3^6Câu trả lời: b: \(=\dfrac{2^4}{2^3}\cdot\dfrac{5^2}{5^3}\cdot\dfrac{11^2}{11}\cdot\dfrac{7}{7^2}=\dfrac{2}{5}\cdot\dfrac{11}{7}=\dfrac{22}{35}\)b: \(=\dfrac{3^3\left(2^3+2^2+1\right)}{-13}=\dfrac{3^3\cdot13}{-13}=-27\)b: \(=\dfrac{2^6\cdot3^6+3^6+3^6\cdot2^3}{73}\)=3^6(2^6+2^3+1)/73=3^6