Question

Answer 1

`a, 8/3x^2y^2. (-1/4x^2y)`.

`= -2/3x^4y^3`.

Hệ số: `-2/3.`

Bậc: `7`.

`b,` Thay `x = -1, y = 1` vào `A`:

`A = -2/3 . (-1)^4 . 1^3`.

`= -2/3`.

Answer 2

a) \(A=\dfrac{8}{3}x^2y^2\cdot\left(-\dfrac{1}{4}x^2y\right)\)

\(A=\left(\dfrac{8}{3}\cdot-\dfrac{1}{4}\right)\left(x^2\cdot x^2\right)\left(y^2\cdot y\right)\)

\(A=-\dfrac{2}{3}x^4y^3\)

Hệ số: \(-\dfrac{2}{3}\)

Bậc: 4+3=7

b) Thay \(x=-1;y=1\) vào A ta có:

\(A=-\dfrac{2}{3}\cdot\left(-1\right)^4\cdot1^3=-\dfrac{2}{3}\)

Vậy: ...