a: Khi x=4 thì \(A=\dfrac{4-1}{4+2}=\dfrac{3}{6}=\dfrac{1}{2}\)
b: A+B
\(=\dfrac{x-1}{x+2}+\dfrac{5x-2}{\left(x-2\right)\left(x+2\right)}\)
\(=\dfrac{x^2-3x+2+5x-2}{\left(x-2\right)\left(x+2\right)}=\dfrac{x^2+2x}{\left(x-2\right)\left(x+2\right)}=\dfrac{x}{x-2}\)
c: A+B=3/2
=>x/x-2=3/2
=>3x-6=2x
=>x=6