b: =>x^3+8+x^2-2x+4=12
=>x^3+x^2-2x+12=12
=>x^3+x^2-2x=0
=>x(x+2)(x-1)=0
=>x=0 hoặc x=1
c: \(\Leftrightarrow6\left(x-4\right)+3\left(3x-4\right)-30x=10\left(2x-5\right)-5\left(7x+3\right)\)
=>\(6x-24+9x-12-30x=20x-50-35x-15\)
=>-15x-36=-15x-65
=>-36=-65(loại)