Question

Answer 1

Bài 3:

\(2x^2+2x=2x\left(x+1\right)\)

\(3x^2-6x=3x\left(x-2\right)\)

=>MTC=6x(x+1)(x-2)

Bài 4:

\(\dfrac{1}{2x^2+2x}=\dfrac{1}{2x\left(x+1\right)}=\dfrac{3\left(x-2\right)}{6x\left(x+1\right)\left(x-2\right)}\)

\(\dfrac{1}{3x^2-6x}=\dfrac{1}{3x\left(x-2\right)}=\dfrac{2\left(x+1\right)}{6x\left(x+1\right)\left(x-2\right)}\)