\(\sqrt{x^2-4}=2-x\)
\(\Leftrightarrow\left\{{}\begin{matrix}2-x\ge0\\x^2-4=\left(2-x\right)^2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\le2\\x^2-4=x^2-4x+4\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}x\le2\\x=2\end{matrix}\right.\)
\(\Rightarrow x=2\)