Question

Answer 1

\(A=\dfrac{x\sqrt{x}+1-\left(x-1\right)\left(\sqrt{x}-1\right)}{x-1}\)

\(=\dfrac{x\sqrt{x}+1-x\sqrt{x}+x+\sqrt{x}-1}{x-1}=\dfrac{\sqrt{x}}{\sqrt{x}-1}\)

Khi x=2016+2căn 2015 thì \(A=\dfrac{\sqrt{2015}+1}{\sqrt{2015}}\)

=>\(A-1=\dfrac{1}{\sqrt{2015}}\)