Bài 3:
a: =>(x-1)(5x-1)=0
=>x=1/5 hoặc x=1
b: =>(x+5)(2-x)=0
=>x=2 hoặc x=-5
Bài 1
a, \(=\left(x-3y\right)^2-49=\left(x-3y-7\right)\left(x-3y+7\right)\)
b, \(=y\left(1-x^2\right)-y^2\left(x+1\right)=y\left(1-x\right)\left(x+1\right)-y^2\left(x+1\right)=\left(x+y\right)\left(y-xy-y^2\right)=y\left(x+y\right)\left(1-x-y\right)\)
c, \(=5x\left(x+y\right)-\left(x+y\right)=\left(5x-1\right)\left(x+y\right)\)