Question

Answer 1

a, \(x\left(x^2-4\right)=0\Leftrightarrow x=0;x=-2;x=2\)

b, \(2x\left(x^2-2x+1\right)=0\Leftrightarrow2x\left(x-1\right)^2=0\Leftrightarrow x=0;x=1\)

c, \(3x^3\left(x^2-2\right)=0\Leftrightarrow x=0;x=\pm\sqrt{2}\)

d, \(\left(x-\dfrac{1}{2}\right)^2=0\Leftrightarrow x=\dfrac{1}{2}\)

Answer 2

a: =>x(x-2)(x+2)=0

hay \(x\in\left\{0;2;-2\right\}\)

b: =>2x(x²-2x+1)=0

=>x(x-1)=0

=>x=0 hoặc x=1

c: =>3x³(x²-2)=0

hay \(x\in\left\{0;\sqrt{2};-\sqrt{2}\right\}\)