\(1,x\left(x-3\right)=0\\ \left[{}\begin{matrix}x=0\\x-3=0\end{matrix}\right.=>x=0;x=3\\ 2,x\left(x+6\right)=0\\ \left[{}\begin{matrix}x=0\\x+6=0\end{matrix}\right.=>x=0;x=-6\\ 3,x\left(2x-7\right)=0\\ \left[{}\begin{matrix}x=0\\2x-7=0\end{matrix}\right.=>x=0;x=\dfrac{7}{2}\\ 4,x\left(3+2x\right)=0\\ \left[{}\begin{matrix}x=0\\3+2x=0\end{matrix}\right.=>x=0;x=-\dfrac{3}{4}\\ 5,x\left(7-x\right)=0\\ \left[{}\begin{matrix}x=0\\7-x=0\end{matrix}\right.=>x=0;x=7\)
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