Câu hỏi của °𝗝𝗲𝘆シ︎°

1: \(\Leftrightarrow x^2-4x+4-3x+6=x^2+6x+9\)=>-7x+10=6x+9=>-13x=-1hay x=1/132: \(\Leftrightarrow x^2+x-6-x^2+6x-9-3x+3\)\(=4x-12\)3: \(\Leftrightarrow3x^2-7x+2-4x^2+12x-9=-x^2-2x-1\)=>5x-7=-2x-1=>7x=6hay x=6/7Câu trả lời: 1: \(\Leftrightarrow x^2-4x+4-3x+6=x^2+6x+9\)=>-7x+10=6x+9=>-13x=-1hay x=1/132: \(\Leftrightarrow x^2+x-6-x^2+6x-9-3x+3\)\(=4x-12\)3: \(\Leftrightarrow3x^2-7x+2-4x^2+12x-9=-x^2-2x-1\)=>5x-7=-2x-1=>7x=6hay x=6/7