Question

Answer 1

a: \(\Leftrightarrow2^{x+1}=32\)

=>x+1=5

hay x=4

b: \(\Leftrightarrow5^{x-3}=5\)

=>x-3=1

hay x=4

c: \(\Leftrightarrow5^{2x-3}=5^2\cdot5=5^3\)

=>2x-3=3

=>2x=6

hay x=3

d: \(\Leftrightarrow2^{x+1}=32\)

=>x+1=5

hay x=4