Question

Answer 1

\(\left(2x-7\right)^2=16\Leftrightarrow\left[{}\begin{matrix}2x-7=4\\2x-7=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)

Answer 2

\(\left(2x-7\right)=\sqrt{16}\)

\(2x-7=4\)

\(2x=11\)

\(x=\dfrac{11}{2}\)

Answer 3

`(2x-7)=sqrt{16}`

`<=> (2x-7)^2 = 16`

`<=>`\(\left[{}\begin{matrix}2x-7=4\\2x-7=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=11\\2x=3\end{matrix}\right.\)

`<=>`\(\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=\dfrac{3}{2}\end{matrix}\right.\)