Bài 51:
a: \(=\dfrac{3-\sqrt{2}+3+\sqrt{2}}{7}=\dfrac{6}{7}\)
b: \(=\dfrac{6\sqrt{2}+8-6\sqrt{2}+8}{18-8}=\dfrac{16}{10}=\dfrac{8}{5}\)
c: \(=\dfrac{8-2\sqrt{15}+8+2\sqrt{15}}{2}=\dfrac{16}{2}=8\)
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