\(a,\dfrac{\dfrac{3}{2}+\dfrac{3}{4}-\dfrac{3}{11}-\dfrac{3}{13}}{\dfrac{5}{2}+\dfrac{5}{4}-\dfrac{5}{11}-\dfrac{5}{13}}\\ =\dfrac{3\left(\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{11}-\dfrac{1}{13}\right)}{5\left(\dfrac{1}{2}+\dfrac{1}{4}-\dfrac{1}{11}-\dfrac{1}{13}\right)}\\ =\dfrac{3}{5}\)
\(b,B=1+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{1-\dfrac{1}{2}}}}\\ =1+\dfrac{1}{1+\dfrac{1}{1+\dfrac{1}{\dfrac{1}{2}}}}\\ =1+\dfrac{1}{1+\dfrac{1}{1+2}}\\ =1+\dfrac{1}{1+\dfrac{1}{3}}\\ =1+\dfrac{1}{\dfrac{4}{3}}\\ =1+\dfrac{3}{4}\\ =\dfrac{7}{4}\)
`A=(3/2 + 3/4 - 3/11 - 3/13)/(5/2 + 5/4 - 5/11 - 5/13)`
`=> A = (3.(1/2 + 1/4 - 1/11 - 1/13))/(5.(1/2 + 1/4 - 1/11 - 1/13))`
`=> A = (3.1)/(5.1)`
`=> A = 3/5`
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`B=1 + 1/(1 + (1 + 1/(1-1/2)))`
`=> B = 1 + 1/(1 + (1 + (1/1/2)))`
`=> B = 1 + 1/(1 + (1 + 1/3))`
`=> B = 1 + (1/4/3)`
`=> B = 1 + 3/4`
`=> B = 7/4`