Question

Answer 1

`[3x+5]/2-1 <= [x+2]/3+x`

`<=>[3(3x+5)-6]/6 <= [2(x+2)+6x]/6`

`<=>9x+15-6 <= 2x+4+6x`

`<=>x <= -5`

Vậy `S={x|x <= -5}`

Answer 2

\(\dfrac{3x+5}{2}-1\le\dfrac{x+2}{3}+x\\ \Leftrightarrow3\left(2x+5\right)-6\le2\left(x+2\right)+6x\\ \Leftrightarrow9x+15-6\le2x+4+6x\\ \Leftrightarrow9x-2x-6x\le4-15+6\\ \Leftrightarrow x\le-5\)

Vậy ...