Question

Answer 1

Sửa đề: ...:1/căn x+1+1

a: \(P=\dfrac{\sqrt{x}+1-2\sqrt{x}+2-3\sqrt{x}}{x-1}:\dfrac{1}{\sqrt{x}+1}+1\)

\(=\dfrac{-4\sqrt{x}+3}{x-1}\cdot\dfrac{\sqrt{x}+1}{1}+1\)

\(=\dfrac{-4\sqrt{x}+3}{\sqrt{x}-1}+1\)

\(=\dfrac{-4\sqrt{x}+3+\sqrt{x}-1}{\sqrt{x}-1}=\dfrac{-5\sqrt{x}+2}{\sqrt{x}-1}\)

b: P<2

=>P-2<0

=>\(\dfrac{-5\sqrt{x}+2-2\sqrt{x}+2}{\sqrt{x}-1}< 0\)

=>\(\dfrac{7\sqrt{x}-4}{\sqrt{x}-1}>0\)

=>x>1 hoặc 0<x<16/49