ĐKXĐ: \(x\ne\left\{2;4\right\}\)
\(\dfrac{\left(x-1\right)\left(x-4\right)}{\left(x-2\right)\left(x-4\right)}+\dfrac{2}{\left(x-2\right)\left(x-4\right)}=\dfrac{\left(x+3\right)\left(x-2\right)}{\left(x-2\right)\left(x-4\right)}\)
\(\Rightarrow\left(x-1\right)\left(x-4\right)+2=\left(x+3\right)\left(x-2\right)\)
\(\Leftrightarrow x^2-5x+4+2=x^2+x-6\)
\(\Leftrightarrow6x=12\)
\(\Leftrightarrow x=2\) (ktm ĐKXĐ)
Vậy pt đã cho vô nghiệm
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