Câu hỏi của Phương Anh

a: \(=\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\)b: \(=\dfrac{3}{4}+\dfrac{9}{5}\cdot\dfrac{2}{3}-1=-\dfrac{1}{4}+\dfrac{6}{5}=\dfrac{-5+24}{20}=\dfrac{19}{20}\)c: \(=\dfrac{3}{2}\cdot\dfrac{-3+2}{4}=\dfrac{-3}{8}\)d: \(=\dfrac{-3}{2}\cdot\dfrac{-13}{3}=\dfrac{13}{2}\)Câu trả lời: a: \(=\dfrac{2}{3}+\dfrac{1}{5}\cdot\dfrac{10}{7}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{20}{21}\)b: \(=\dfrac{3}{4}+\dfrac{9}{5}\cdot\dfrac{2}{3}-1=-\dfrac{1}{4}+\dfrac{6}{5}=\dfrac{-5+24}{20}=\dfrac{19}{20}\)c: \(=\dfrac{3}{2}\cdot\dfrac{-3+2}{4}=\dfrac{-3}{8}\)d: \(=\dfrac{-3}{2}\cdot\dfrac{-13}{3}=\dfrac{13}{2}\)