Câu hỏi của vicbin vicbin

\(P=\left(\dfrac{x+\sqrt{x}+1-x+\sqrt{x}-1}{\sqrt{x}}\right)\cdot\dfrac{x-2}{x+2}=\dfrac{2\left(x-2\right)}{x+2}=\dfrac{2x-4}{x+2}\)Câu trả lời: \(P=\left(\dfrac{x+\sqrt{x}+1-x+\sqrt{x}-1}{\sqrt{x}}\right)\cdot\dfrac{x-2}{x+2}=\dfrac{2\left(x-2\right)}{x+2}=\dfrac{2x-4}{x+2}\)