1: Khi x=3 thì \(A=\dfrac{3-1}{3^2}=\dfrac{2}{9}\)
2: \(B=\dfrac{2x+1-x^2+2x^2-3x-1}{x\left(2x+1\right)}=\dfrac{x^2-x}{x\left(2x+1\right)}=\dfrac{x-1}{2x+1}\)
3: C=A:B
\(=\dfrac{x-1}{x^2}\cdot\dfrac{2x+1}{x-1}=\dfrac{2x+1}{x^2}\)
C+1=(2x+1+x^2)/x^2=(x+1)^2/x^2>=0
=>C>=-1