Question

Answer 1

a: \(=\dfrac{14}{3}+\dfrac{7}{2}=\dfrac{28+21}{6}=\dfrac{49}{6}\)

b: \(=\dfrac{14}{3}\cdot\dfrac{-7}{2}=\dfrac{-49}{3}\)

c: \(=\dfrac{11}{3}+\dfrac{7}{2}:\dfrac{4}{3}=\dfrac{11}{3}+\dfrac{7}{2}\cdot\dfrac{3}{4}=\dfrac{11}{3}+\dfrac{21}{8}=\dfrac{151}{24}\)

d: \(=\dfrac{7}{2}\cdot\dfrac{7}{3}=\dfrac{49}{6}\)

e: \(=\dfrac{14}{3}:\dfrac{15}{4}=\dfrac{14}{3}\cdot\dfrac{4}{15}=\dfrac{56}{45}\)