a: \(P=\dfrac{x^2-4x+4+x^2+2x-2x-4}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x-3+5}{x-3}\)
\(=\dfrac{2x^2-4x}{\left(x-2\right)\left(x+2\right)}\cdot\dfrac{x+2}{x-3}\)
=2x/x-3
b: x^2-3x+2=0
=>x=1(nhận) hoặc x=2(loại)
Khi x=1 thì \(P=\dfrac{2\cdot1}{1-3}=\dfrac{2}{-2}=-1\)