\(B=\dfrac{x}{3}+\dfrac{12}{5x+10}=\dfrac{x+2}{3}+\dfrac{12}{5\left(x+2\right)}-\dfrac{2}{3}\ge2\sqrt{\dfrac{12\left(x+2\right)}{15\left(x+2\right)}}-\dfrac{2}{3}=\dfrac{12\sqrt{5}-10}{15}\)
Dấu "=" xảy ra khi \(\dfrac{x+2}{3}=\dfrac{12}{5\left(x+2\right)}\Rightarrow x=\dfrac{6\sqrt{5}-10}{5}\)