Question

 
 

 

Answer 1

\(A=3x^2y^3-5x^2+3x^3y^2\)bậc 5 

\(B=\dfrac{5}{2}x^5y^2+\dfrac{7}{3}xy^4-\dfrac{1}{4}x^2y^3\)bậc 7 

Answer 2

$\mathrm{Thu\; gọn}$:${}^{}{}^{}+7{}^{}-8{}^{}{}^{}-12{}^{}+11{}^{}{}^{}-12{}^{}{}^{}$Trừ $12{}^{}{}^{}$ từ $15{}^{}{}^{}$.$7{}^{}-8{}^{}{}^{}-12{}^{}+11{}^{}{}^{}+3{}^{}{}^{}$ Trừ $12{}^{}$ từ