=>5(2x-5)=3x+15
=>10x-25=3x+15
=>7x=40
hay x=40/7
\(\dfrac{2x-5}{x+5}=\dfrac{3}{5}\\ ĐKXĐ:x\ne-5\\ \Leftrightarrow\dfrac{5\left(2x-5\right)}{5x+25}=\dfrac{3x+15}{5x+25}\\ \Leftrightarrow10x-25=3x+15\\ \Leftrightarrow10x-3x=15+20\\ \Leftrightarrow7x=40\\ \Leftrightarrow x=\dfrac{40}{7}\left(nhận\right)\)