3/
\(\Leftrightarrow2x^3+6x^2-x^2-3x=0\)
\(\Leftrightarrow2x^2\left(x+3\right)-x\left(x+3\right)=0\\ \Leftrightarrow\left(x+3\right)\left(2x^2-x\right)=0\)
\(\Leftrightarrow x\left(x+3\right)\left(2x-1\right)=0\\ \Leftrightarrow x=0;x=-3;x=\dfrac{1}{2}\)
1/\(\Leftrightarrow\left(x-2\right)\left(3x-1\right)-x\left(2-x\right)=0\\ \Leftrightarrow\left(x-2\right)\left(3x-1\right)+x\left(x-2\right)=0\)
\(\Leftrightarrow\left(x-2\right)\left(3x-1+x\right)=0\\ \Leftrightarrow\left(x-2\right)\left(4x-1\right)=0\Leftrightarrow x-2=0;4x-1=0\)
\(\Leftrightarrow x=2;x=\dfrac{1}{4}\)
2/
\(\Leftrightarrow\left(2x-3\right)\left(2x-3\right)-\left(2x-3\right)\left(x+1\right)=0\\ \Leftrightarrow\left(2x-3\right)\left(2x-3-x-1\right)=0\)
\(\Leftrightarrow\left(2x-3\right)=0;x-4=0\\ \Leftrightarrow x=\dfrac{3}{2};x=4\)
7: =>(x-2)(3x-3)=0
=>x=2 hoặc x=1
9: =>(x-3)(2x-4)=0
=>x=3 hoặc x=2
8: =>2x-1=5 hoặc 2x-1=-5
=>2x=6 hoặc 2x=-4
=>x=3 hoặc x=-2
10: =>(3x+1)(3x-1)-(3x+1)(4x+1)=0
=>(3x+1)(-x-2)=0
=>x=-1/3 hoặc x=-2
4/
\(\Leftrightarrow3\left(x-5\right)-2x\left(x-5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(3-2x\right)=0\Leftrightarrow x=5;x=\dfrac{3}{2}\)
5/
\(\Leftrightarrow4x\left(x+1\right)+\left(1-x^2\right)=0\\ \Leftrightarrow4x\left(x+1\right)+\left(1-x\right)\left(1+x\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(4x+1-x\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(3x+1\right)=0\Rightarrow x=-1;x=-\dfrac{1}{3}\)
6/
\(\Leftrightarrow2x^2-9x-\left(3x^2-15x\right)=0\\ \Leftrightarrow2x^2-9x-3x^2+15x=0\)
\(\Leftrightarrow6x-x^2=0\)
\(\Leftrightarrow x\left(6-x\right)=0;\Rightarrow x=0;x=6\)
7/
\(\Leftrightarrow3x\left(x-2\right)-3\left(x-2\right)=0\Leftrightarrow\left(x-2\right)\left(3x-3\right)=0\\ \Leftrightarrow3\left(x-2\right)\left(x-1\right)=0\)
\(\Rightarrow x=2;x=1\)
8/
\(\Leftrightarrow\left(2x-1\right)^2-5^2=0\Leftrightarrow\left(2x-1-5\right)\left(2x-1+5\right)=0\)
\(\Rightarrow\left(2x-6\right)=0;\left(2x+4\right)=0\\ \Rightarrow x=3;x=-2\)
mấy câu sau tương tự như thế bn thử giải xem câu nèo k bt ns t dc hem:>
