Question

Answer 1

a: =>4x+4<6+3x-6

=>4x-3x<-4

hay x<-4

b: =>2x+3>=4-x

=>2x+x>=4-3

=>3x>=1

hay x>=1/3

Answer 2

a, \(\dfrac{2x+2}{3}< 2+\dfrac{x-2}{2}\Leftrightarrow\dfrac{4x+4}{6}-\dfrac{12}{6}-\dfrac{3x-6}{6}< 0\)

\(\Leftrightarrow\dfrac{4x+4-12-3x+6}{6}< 0\Rightarrow x-2< 0\Leftrightarrow x< 2\)

b, \(\dfrac{2x+3}{-4}\ge\dfrac{x-4}{3}\Leftrightarrow\dfrac{-2x-3}{4}-\dfrac{x-4}{3}\ge0\)

\(\Leftrightarrow\dfrac{-6x-9-4x+16}{12}\ge0\Rightarrow-10x+7\ge0\Leftrightarrow x\le\dfrac{7}{10}\)