Câu hỏi của Trinhdiem

a: \(=15x^3y^2-x^3y^3+6x^2y^3\)b: \(=x^2-4x+4+x^2-10x+25+2\left(5x-x^2-10+2x\right)\)\(=2x^2-14x+29+2\left(-x^2+7x-10\right)\)\(=2x^2-14x+29-2x^2+14x-20=9\)c: \(=\dfrac{x^4-2x^3+3x^2+x^3-2x^2+3x}{x^2-2x+3}=x^2+x\)Câu trả lời: a: \(=15x^3y^2-x^3y^3+6x^2y^3\)b: \(=x^2-4x+4+x^2-10x+25+2\left(5x-x^2-10+2x\right)\)\(=2x^2-14x+29+2\left(-x^2+7x-10\right)\)\(=2x^2-14x+29-2x^2+14x-20=9\)c: \(=\dfrac{x^4-2x^3+3x^2+x^3-2x^2+3x}{x^2-2x+3}=x^2+x\)