a: \(\left\{{}\begin{matrix}a+b=0\\-5a+b=2\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}6a=-2\\b=-a\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=-\dfrac{1}{3}\\b=\dfrac{1}{3}\end{matrix}\right.\)
Đúng 0
Bình luận (0)