Question

Answer 1

\(\left(4x-1\right)^{30}=\left(4x-1\right)^{20}\\ \Rightarrow\left(4x-1\right)^{30}-\left(4x-1\right)^{20}=0\\ \Rightarrow4x-1=0;1\\ TH1:4x-1=0\\ 4x=1\\ x=\dfrac{1}{4}\\ TH2:4x-1=1\\ 4x=2\\ x=\dfrac{1}{2}\)