Question

Answer 1

\(\dfrac{27^4.4^3}{9^5.8^2}\)

\(=\dfrac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}\)

\(=\dfrac{3^{12}.2^6}{3^{10}.2^6}\)

\(=3^2=9\)

Answer 2

Bài 1:

a) \(\left(\dfrac{2}{3}-\dfrac{1}{2}\right)^2+\dfrac{-7}{15}:1\dfrac{2}{5}=\left(\dfrac{1}{6}\right)^2+\dfrac{-7}{15}.\dfrac{5}{7}=\dfrac{1}{36}+\dfrac{-1}{3}=\dfrac{1+\left(-12\right)}{36}=\dfrac{-11}{36}\)b) \(\dfrac{27^4.4^3}{9^5.8^2}=\dfrac{\left(3^3\right)^4.\left(2^2\right)^3}{\left(3^2\right)^5.\left(2^3\right)^2}=\dfrac{3^{12}.2^6}{3^{10}.2^6}=3^2=9\)