\(a,\Leftrightarrow\left(3x-\dfrac{1}{5}\right)^2=\dfrac{9}{25}\Leftrightarrow\left[{}\begin{matrix}3x-\dfrac{1}{5}=\dfrac{3}{5}\\3x-\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{4}{15}\\x=-\dfrac{2}{15}\end{matrix}\right.\\ b,\Leftrightarrow\left[{}\begin{matrix}2,3-x=0,2\\x-2,3=0,2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2,1\\x=2,5\end{matrix}\right.\)
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