Câu hỏi của olivouz____ha

Bài 5: a: Ta có: \(\sqrt{x-1}=\sqrt{2006}\)\(\Leftrightarrow x-1=2006\)hay x=2007b: Ta có: \(\sqrt{5-2x}=5-\sqrt{2}\)\(\Leftrightarrow-2x+5=27-10\sqrt{5}\)\(\Leftrightarrow-2x=22-10\sqrt{5}\)hay \(x=-11+5\sqrt{5}\)Câu trả lời: Bài 5: a: Ta có: \(\sqrt{x-1}=\sqrt{2006}\)\(\Leftrightarrow x-1=2006\)hay x=2007b: Ta có: \(\sqrt{5-2x}=5-\sqrt{2}\)\(\Leftrightarrow-2x+5=27-10\sqrt{5}\)\(\Leftrightarrow-2x=22-10\sqrt{5}\)hay \(x=-11+5\sqrt{5}\)