ĐKXĐ: \(x\ge1\)
\(\sqrt{4\left(x+1\right)}+\sqrt{16\left(x+1\right)}+\sqrt{25\left(x+1\right)}=3\)
\(\Leftrightarrow2\sqrt{x+1}+4\sqrt{x+1}+5\sqrt{x+1}=3\)
\(\Leftrightarrow11\sqrt{x+1}=3\)
\(\Leftrightarrow\sqrt{x+1}=\dfrac{3}{11}\)
\(\Leftrightarrow x+1=\dfrac{9}{121}\)
\(\Rightarrow x=-\dfrac{112}{121}\) (thỏa mãn)