Question

Answer 1

a)\(\dfrac{-7}{2}+\dfrac{3}{4}-\dfrac{17}{12}\)

\(=\dfrac{-42}{12}+\dfrac{9}{12}-\dfrac{17}{12}\)

\(=\dfrac{-33}{12}-\dfrac{17}{12}\)

\(=\dfrac{-50}{12}\)\(=\dfrac{-25}{6}\)

Answer 2

\(a,=\dfrac{-42+9-17}{12}=-\dfrac{57}{12}=-\dfrac{19}{4}\\ b,=-\dfrac{5}{6}+\dfrac{3}{8}-\dfrac{1}{10}=\dfrac{-100+45-12}{120}=\dfrac{-67}{120}\)

Answer 3

\(a,\dfrac{-7}{2}+\dfrac{3}{4}-\dfrac{17}{12}=\dfrac{-42}{12}+\dfrac{9}{12}-\dfrac{17}{12}=\dfrac{-25}{6}\)

\(d,-\dfrac{5}{6}-\left(-\dfrac{3}{8}+\dfrac{1}{10}\right)=-\dfrac{5}{6}+\dfrac{1}{40}=\dfrac{103}{120}\)

Answer 4

bài 2)

a)\(\dfrac{-7}{2}+\dfrac{3}{4}-\dfrac{17}{12}\)

\(=\dfrac{-42}{12}+\dfrac{9}{12}-\dfrac{17}{12}\)

\(=\dfrac{-33}{12}-\dfrac{17}{12}\)

\(=\dfrac{-50}{12}\)

\(=\dfrac{-25}{6}\)

b)\(-\dfrac{5}{6}-\left(-\dfrac{3}{8}+\dfrac{1}{10}\right)\)

\(=-\dfrac{5}{6}+\dfrac{3}{8}-\dfrac{1}{10}\)

\(=-\dfrac{40}{48}+\dfrac{18}{48}-\dfrac{1}{10}\)

\(=\dfrac{-22}{48}-\dfrac{1}{10}\)

\(=\dfrac{-11}{24}-\dfrac{1}{10}\)

\(=\dfrac{-110}{240}-\dfrac{24}{240}\)

\(=\dfrac{-134}{240}\)

\(=\dfrac{-67}{120}\)

 

Answer 5

d)\(\dfrac{-5}{6}-\left(\dfrac{-3}{8}+\dfrac{1}{10}\right)\)

\(=\dfrac{-5}{6}-\left(\dfrac{-30}{80}+\dfrac{8}{80}\right)\)

\(=\dfrac{-5}{6}-\left(-\dfrac{28}{80}\right)\)

\(=-\dfrac{29}{60}\)