Question

Answer 1

giúp với

 

Answer 2

1: Thay x=9 vào B, ta được:

\(B=\dfrac{3+1}{9-2\cdot3+1}=\dfrac{4}{4}=1\)

2: Ta có: P=A:B

\(=\left(\dfrac{1}{x-\sqrt{x}}+\dfrac{1}{\sqrt{x}-1}\right):\dfrac{\sqrt{x}+1}{x-2\sqrt{x}+1}\)

\(=\dfrac{1+\sqrt{x}}{\sqrt{x}\left(\sqrt{x}-1\right)}\cdot\dfrac{\left(\sqrt{x}-1\right)^2}{\sqrt{x}+1}\)

\(=\dfrac{\sqrt{x}-1}{\sqrt{x}}\)